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x^2-15.5x+49.5=0
a = 1; b = -15.5; c = +49.5;
Δ = b2-4ac
Δ = -15.52-4·1·49.5
Δ = 42.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15.5)-\sqrt{42.25}}{2*1}=\frac{15.5-\sqrt{42.25}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15.5)+\sqrt{42.25}}{2*1}=\frac{15.5+\sqrt{42.25}}{2} $
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